[IPython-dev] crtl+c annotations in zmq terminal for suggestions

Omar Andrés Zapata Mesa andresete.chaos@gmail....
Tue Sep 13 14:01:15 CDT 2011


hi all.
Doing some tests in the zmq frontend I find the next things
from minrk repo  git://github.com/minrk/ipython.git in the branch termzmq

->open a new kernel but not using
 ipython/IPython/frontend/zmqterminal/app.py
just run python -c "from IPython.zmq.ipkernel import main; main()"

 python -c "from IPython.zmq.ipkernel import main; main()"
[IPKernelApp] To connect another client to this kernel, use:
[IPKernelApp] --existing --shell=49587 --iopub=57815 --stdin=55774
--hb=33990

if you press crtl+c the kernel output is
^CKeyboardInterrupt caught in kernel
that is right!!

-> open in other console
python app.py  --existing --shell=49587 --iopub=57815 --stdin=55774
--hb=33990

and press crtl+c
output

KeyboardInterrupt
---------------------------------------------------------------------------
RuntimeError                              Traceback (most recent call last)
/usr/local/lib/python2.6/dist-packages/IPython/frontend/terminal/interactiveshell.pyc
in raw_input(self, prompt)

    338
    339         try:
--> 340             line =
raw_input_original(prompt).decode(self.stdin_encoding)
    341         except ValueError:
    342             warn("\n********\nYou or a %run:ed script called
sys.stdin.close()"

/home/omazapa/MyProjects/ipython/IPython/frontend/zmqterminal/app.py in
handle_sigint(self, *args)

    143         # FIXME: this doesn't work, the kernel just dies every time

    144         self.shell.write('KeyboardInterrupt\n')
--> 145         self.kernel_manager.interrupt_kernel()
    146
    147     def init_code(self):

/usr/local/lib/python2.6/dist-packages/IPython/zmq/kernelmanager.pyc in
interrupt_kernel(self)

    916                 self.kernel.send_signal(signal.SIGINT)
    917         else:
--> 918             raise RuntimeError("Cannot interrupt kernel. No kernel
is running!")

    919
    920     def signal_kernel(self, signum):

RuntimeError: Cannot interrupt kernel. No kernel is running!

-> it produces a ugly traceback but the kernel is not die.
-> any know why is tell me that  No kernel is running? (but the kernel is
running)
-> calling ipkernel directly show the next traceback


-- 
Omar Andres Zapata Mesa
Head Developer Phenomenology of Fundamental Interactions Group (Gfif)
http://gfif.udea.edu.co
Division of computer science Gfif Developers (Gfif Dev)
http://gfifdev.udea.edu.co
Systems Engineering Student
Universidad de Antioquia At Medellin - Colombia
Usuario Linux  #490962
-------------- next part --------------
An HTML attachment was scrubbed...
URL: http://mail.scipy.org/pipermail/ipython-dev/attachments/20110913/b63e7ea4/attachment.html 


More information about the IPython-dev mailing list