[IPython-dev] IPython-dev Digest, Vol 121, Issue 28

TARUN GABA tarun.gaba7@gmail....
Thu Feb 20 23:41:35 CST 2014


So the function I mention is supposed to open the browser with a specific
url.
Now if it is called from ipython notebook,  a browser is already open, so
it simply opens up a new tab.
If the method is called from command line interpreter or qtconsole instead
of popping up a browser window (some people find it irritating), we can
display a message that requests them to manually open browser and move to
that url. What is the best approach for this?
On 20 Feb 2014 23:35, <ipython-dev-request@scipy.org> wrote:

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>    1. Best way to detect IPython notebook (TARUN GABA)
>    2. Re: Best way to detect IPython notebook (Matthias BUSSONNIER)
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> Message: 1
> Date: Thu, 20 Feb 2014 22:15:33 +0530
> From: TARUN GABA <tarun.gaba7@gmail.com>
> Subject: [IPython-dev] Best way to detect IPython notebook
> To: ipython-dev@scipy.org
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> UdE_pUX19ZTYAxLQMyZMi3AdA@mail.gmail.com>
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>
> Hi,
> I have written a method, which behaves differently when called from IPython
> notebook, and from interpreter/qtconsole respectively.
> I need to detect whether the method is called from notebook or interpreter.
> This was the code I was using till now.
>
>     if get_ipython().config['KernelApp']['parent_appname'] ==
> 'ipython-notebook':
>         ##Do something
>
> But I have came to know that this particular dict changes its format in
> different IPython versions(I am not sure how many changes are there).
>
> Is there any better method to achieve this?
> Thanks in advance :)
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> ------------------------------
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> Message: 2
> Date: Thu, 20 Feb 2014 18:17:54 +0100
> From: Matthias BUSSONNIER <bussonniermatthias@gmail.com>
> Subject: Re: [IPython-dev] Best way to detect IPython notebook
> To: IPython developers list <ipython-dev@scipy.org>
> Message-ID: <6CC95483-B554-40C9-91AB-DB63FCDE0AA3@gmail.com>
> Content-Type: text/plain; charset=iso-8859-1
>
> Hi,
>
> Le 20 f?vr. 2014 ? 17:45, TARUN GABA a ?crit :
>
> > Hi,
> > I have written a method, which behaves differently when called from
> IPython notebook, and from interpreter/qtconsole respectively.
> > I need to detect whether the method is called from notebook or
> interpreter.
> > This was the code I was using till now.
> >
> >     if get_ipython().config['KernelApp']['parent_appname'] ==
> 'ipython-notebook':
> >         ##Do something
> >
> > But I have came to know that this particular dict changes its format in
> different IPython versions(I am not sure how many changes are there).
> >
> > Is there any better method to achieve this?
>
> You should describe what you ment by "called from a notebook"
> it is not clear enough to give a correct answer.
>
> But if the question is the same as usual, and as stated in many discussion
> scattered
> over the net and mailing list, there is no, and there will be no reliable
> way to detect which
> frontend are requiring code execution, as there is no reason for a kernel
> to be connected
> to only one frontend.
>
> It is like a book writer asking "how can I make the eye color of my main
> character the same as my reader" ?
> The question make no sense as two person can be reading the same page of
> the same book at the same time.
>
> And as usual, if you describe what you are trying to archive instead of
> how,
> you might get an answer that suit you.
>
>
> Cheers,
> --
> Matthias
>
>
>
>
> > Thanks in advance :)
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