[IPython-user] More ipython and python2.5: 'with' statements

Zachary Pincus zpincus at stanford.edu
Thu Mar 9 19:16:57 CST 2006


Hi folks,

In python 2.6, 'with' and 'as' will become keywords (see http:// 
www.python.org/doc/peps/pep-0343/ ). Python 2.5 gives a warning about  
these symbols if used, and 'with blocks' can be used with a 'from  
__future__ import with_statement' line.

However, ipython seems to somehow cause 'with' and 'as' to be treated  
as reserved keywords even if no 'from __future__' line is executed.  
(See below for example.)

I'm not sure how this is happening. Any thoughts?

Zach


  zpincus% python
Python 2.5a0 (trunk:42924M, Mar  8 2006, 19:29:24)
[GCC 4.0.1 (Apple Computer, Inc. build 5250)] on darwin
 >>> with = 5
<stdin>:1: Warning: 'with' will become a reserved keyword in Python 2.6
 >>> from __future__ import with_statement
 >>> with = 5
   File "<stdin>", line 1
     with = 5
          ^
SyntaxError: invalid syntax

zpincus% ipython
In [1]: with = 5
------------------------------------------------------------
    File "<ipython console>", line 1
      with = 5
           ^
<class 'exceptions.SyntaxError'>: invalid syntax






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