[IPython-User] simple iPython example raises exception on sys.exit()
Dave
davestechshop@gmail....
Mon Jun 4 16:24:31 CDT 2012
I'm doing some very simple PySide (and PyQt) tutorials in iPython. One
tutorial just creates a window with some sliders to demonstrate slots and
signals.
When I close the window of the running demo application, I see this error:
An exception has occurred, use %tb to see the full traceback.
SystemExit: 0
To exit: use 'exit', 'quit', or Ctrl-D.
So I run %tb and get this:
SystemExit Traceback (most recent call last)
/Workspaces/scratch/<ipython-input-1-88966dcfb499> in <module>()
33
34 if __name__ == "__main__":
---> 35 main()
/Workspaces/scratch/<ipython-input-1-88966dcfb499> in main()
29 w.show()
30 app.exec_()
---> 31 sys.exit(0)
32
33
SystemExit: 0
If I try to execute my code again, I get this:
RuntimeError: A QApplication instance already exists.
In case it helps, here my code:
from PySide.QtCore import *
from PySide.QtGui import *
import sys
class MyWindow(QWidget):
def __init__(self):
QWidget.__init__(self, None)
vbox = QVBoxLayout(self)
self.slider1 = QSlider(Qt.Horizontal)
self.slider1.setRange(0, 99)
self.slider1.setValue(0)
vbox.addWidget(self.slider1)
self.slider2 = QSlider(Qt.Horizontal)
self.slider2.setRange(0, 99)
self.slider2.setValue(99)
vbox.addWidget(self.slider2)
self.slider1.valueChanged.connect(self.slider2Changed)
def slider2Changed(self, position):
self.slider2.setValue(self.slider2.maximum() - position)
def main():
app = QApplication(sys.argv)
w = MyWindow()
w.show()
app.exec_()
sys.exit(0)
if __name__ == "__main__":
main()
I do not have errors when running the code using python:
python myexample.py
This error only happens when I run the code in an iPython (including a
notebook or the qtconsole or the regular ipython terminal).
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