[Numpy-discussion] upcast
Lars Friedrich
lfriedri at imtek.de
Wed Aug 30 11:39:43 CDT 2006
Hello,
I would like to discuss the following code:
#***start***
import numpy as N
a = N.array((200), dtype = N.uint8)
print (a * 100) / 100
b = N.array((200, 200), dtype = N.uint8)
print (b * 100) / 100
#***stop***
The first print statement will print "200" because the uint8-value is
cast "upwards", I suppose. The second statement prints "[0 0]". I
suppose this is due to overflows during the calculation.
How can I tell numpy to do the upcast also in the second case, returning
"[200 200]"? I am interested in the fastest solution regarding execution
time. In my application I would like to store the result in an
Numeric.UInt8-array.
Thanks for every comment
Lars
More information about the Numpy-discussion
mailing list