[Numpy-discussion] Re: Efficient way to handle None->nan?
Russell E. Owen
rowen at cesmail.net
Tue Jan 24 14:01:06 CST 2006
In article <43D16C31.3060209 at ee.byu.edu>,
Travis Oliphant <oliphant at ee.byu.edu> wrote:
> Russell E. Owen wrote:
> >We're getting numeric data from a (MySQL) database. We'd like to use
> >numarray or NumPy on the resulting data, but some values may be None. Is
> >there a fast, efficient way to replace None with NaN? I'd hate to use a
> >list comprehension on each data tuple before turning it into an array,
> >but I haven't thought of anything else.
> Current numpy SVN allows
> array([ 1. , nan, 2. ])
That's great! Thanks!!
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