Assign NaN, get zero

[Stefan van der Walt]

On Sat, Nov 11, 2006 at 01:59:40PM -0800, Keith Goodman wrote:
> Would it make sense to upcast instead of downcast?
> 
> This upcasts:
> 
> >> x = M.matrix([[1, M.nan, 3]])
> >> x
> matrix([[ 1.        ,         nan,  3.        ]])
> 
> But this doesn't:
> 
> >> x = M.matrix([[1, 2, 3]])
> >> x[0,1] = M.nan
> >> x
> matrix([[1, 0, 3]])

This behaviour is consistent with

x = N.array([[1,2.0,3]])

vs

x = N.array([1,2,3])
x[0,1] = 2.

> (BTW, how do you represent missing integers if you can't use NaN?)

I think masked arrays should work on integer arrays (alternatively, if
you have enough memory, cast your array to float).

Regards
Stéfan

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