can this be made faster?

Bill Baxter wbaxter at gmail.com
Sun Oct 8 00:48:59 CDT 2006


Yes, that'd be
   a[b] += c

On 10/8/06, Daniel Mahler <dmahler at gmail.com> wrote:
> Is there a 'loop free' way to do this in Numeric
>
> for i in arange(l):
>    a[b[i]]+=c[i]
>
> where l == len(b) == len(c)
>
> thanks
> Daniel

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