can this be made faster?

Daniel Mahler dmahler at gmail.com
Sun Oct 8 01:03:38 CDT 2006


Thanks Bill.
Thats what I was hoping for,
but I get

>>> a
array([0, 0])
>>> b
array([0, 1, 0, 1, 0])
>>> c
array([1, 1, 1, 1, 1])
>>> a[b]+=c
Traceback (most recent call last):
  File "<stdin>", line 1, in ?
IndexError: invalid index

whereas i would like to get

array([3, 2])



On 10/8/06, Bill Baxter <wbaxter at gmail.com> wrote:
> Yes, that'd be
>    a[b] += c
>
> On 10/8/06, Daniel Mahler <dmahler at gmail.com> wrote:
> > Is there a 'loop free' way to do this in Numeric
> >
> > for i in arange(l):
> >    a[b[i]]+=c[i]
> >
> > where l == len(b) == len(c)
> >
> > thanks
> > Daniel
>
> -------------------------------------------------------------------------
> Take Surveys. Earn Cash. Influence the Future of IT
> Join SourceForge.net's Techsay panel and you'll get the chance to share your
> opinions on IT & business topics through brief surveys -- and earn cash
> http://www.techsay.com/default.php?page=join.php&p=sourceforge&CID=DEVDEV
> _______________________________________________
> Numpy-discussion mailing list
> Numpy-discussion at lists.sourceforge.net
> https://lists.sourceforge.net/lists/listinfo/numpy-discussion
>

-------------------------------------------------------------------------
Take Surveys. Earn Cash. Influence the Future of IT
Join SourceForge.net's Techsay panel and you'll get the chance to share your
opinions on IT & business topics through brief surveys -- and earn cash
http://www.techsay.com/default.php?page=join.php&p=sourceforge&CID=DEVDEV




More information about the Numpy-discussion mailing list