Should numpy.sqrt(-1) return 1j rather than nan?
Sven Schreiber
svetosch at gmx.net
Wed Oct 11 15:46:59 CDT 2006
Travis Oliphant schrieb:
>
>> If not, shouldn't
>>
>>
>> numpy.sqrt(-1) raise a ValueError instead of returning silently nan?
>>
>>
> This is user adjustable. You change the error mode to raise on
> 'invalid' instead of pass silently which is now the default.
>
> -Travis
>
Could you please explain how this adjustment is done, or point to the
relevant documentation.
Thank you,
Sven
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