Should numpy.sqrt(-1) return 1j rather than nan?

Sven Schreiber svetosch at gmx.net
Wed Oct 11 15:46:59 CDT 2006


Travis Oliphant schrieb:

> 
>> If not, shouldn't
>>  
>>
>> numpy.sqrt(-1) raise a ValueError instead of returning silently nan?
>>  
>>
> This is user adjustable.  You change the error mode to raise on 
> 'invalid' instead of pass silently which is now the default.
> 
> -Travis
> 

Could you please explain how this adjustment is done, or point to the
relevant documentation.
Thank you,
Sven

-------------------------------------------------------------------------
Using Tomcat but need to do more? Need to support web services, security?
Get stuff done quickly with pre-integrated technology to make your job easier
Download IBM WebSphere Application Server v.1.0.1 based on Apache Geronimo
http://sel.as-us.falkag.net/sel?cmd=lnk&kid=120709&bid=263057&dat=121642




More information about the Numpy-discussion mailing list