Should numpy.sqrt(-1) return 1j rather than nan?
Travis Oliphant
oliphant.travis at ieee.org
Thu Oct 12 01:40:18 CDT 2006
David Goldsmith wrote:
> Travis Oliphant wrote:
>
>> What could be simpler? ;-)
>>
> Having sqrt(-1) return 1j (without having to remember that in order to
> get this, you have to write sqrt(-1+0j) instead).
>
>
That's exactly what scipy.sqrt(-1) does. That was my point.
-Travis
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