Should numpy.sqrt(-1) return 1j rather than nan?

Travis Oliphant oliphant.travis at ieee.org
Thu Oct 12 01:40:18 CDT 2006


David Goldsmith wrote:
> Travis Oliphant wrote:
>   
>> What could be simpler? ;-)
>>     
> Having sqrt(-1) return 1j (without having to remember that in order to 
> get this, you have to write sqrt(-1+0j) instead).
>
>   
That's exactly what scipy.sqrt(-1) does.  That was my point.

-Travis


-------------------------------------------------------------------------
Using Tomcat but need to do more? Need to support web services, security?
Get stuff done quickly with pre-integrated technology to make your job easier
Download IBM WebSphere Application Server v.1.0.1 based on Apache Geronimo
http://sel.as-us.falkag.net/sel?cmd=lnk&kid=120709&bid=263057&dat=121642




More information about the Numpy-discussion mailing list