Should numpy.sqrt(-1) return 1j rather than nan?
David Cournapeau
david at ar.media.kyoto-u.ac.jp
Thu Oct 12 01:35:48 CDT 2006
David Goldsmith wrote:
> Travis Oliphant wrote:
>
>> What could be simpler? ;-)
>>
> Having sqrt(-1) return 1j (without having to remember that in order to
> get this, you have to write sqrt(-1+0j) instead).
>
>
But this can sometimes lead to confusing errors hard to track when you
don't want to treat complex numbers. That's one of the thing I hated in
matlab, actually: if you don't want to handle complex numbers, you have
to check regularly for it. So I don't think this is simpler.
David
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