Should numpy.sqrt(-1) return 1j rather than nan?

David Goldsmith David.L.Goldsmith at noaa.gov
Thu Oct 12 20:34:09 CDT 2006


I find that acceptable for my purposes, but is there some way we can 
minimize the "surprise(s)"  for newbies?  (I know some suggestions have 
been put forward in this thread, but I don't know enough to cast a vote 
one way or another for any of those, just a vote for "please do it".)  
And, in closing, I too would like to: thank you very much for all your 
work - despite my "emotional outburst," I am generally very happy using 
numpy and regard it as an excellent product.

DG

Travis Oliphant wrote:
> David Goldsmith wrote:
>
>   
>> Got it.  And if I understand correctly, the import order you specify in 
>> the little mynumpy example you included in your latest response to 
>> Fernando will result in any "overlap" between numpy and 
>> numpy.lib.scimath to call the latter's version of things rather than the 
>> former's, yes?
>>  
>>
>>     
>
> Right.  The last import will be used for any common-names (variables get 
> re-bound to the new functions...)
>
> -Travis
>
>
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