[Numpy-discussion] Oddity with numpy.int64 integer division
David M. Cooke
cookedm@physics.mcmaster...
Tue Apr 24 17:42:44 CDT 2007
On Apr 23, 2007, at 21:35 , David M. Cooke wrote:
>
> Python defines x // y as returning the floor of the division, and x
> % y has the same sign as y. However, in C89, it is implementation-
> defined (i.e., portability-pain-in-the-ass) whether the floor or
> ceil is used when the signs of x and y differ. In C99, the result
> should be truncated. From the C99 spec, sec. 6.5.5, #6:
> When integers are divided, the result of the / operator
> is the algebraic quotient with any fractional part
> discarded.76) If the quotient a/b is representable, the
> expression (a/b)*b + a%b shall equal a.
>
> Numpy follows whatever the C compiler decides to use, because of
> speed-vs.-Python compatibility tradeoff.
Just a followup note: gcc (4.0 and 4.2, at least) with -std=c99
*doesn't* respect this; it still does the platform way (on my MacBook
Core Duo, that's truncation towards zero). The assembly it generates
is identical for gcc -std=c99 and gcc -std=c89
--
|>|\/|<
/------------------------------------------------------------------\
|David M. Cooke http://arbutus.physics.mcmaster.ca/dmc/
|cookedm@physics.mcmaster.ca
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