[Numpy-discussion] arctan2 with complex args
Timothy Hochberg
tim.hochberg@ieee....
Mon Apr 30 09:49:57 CDT 2007
On 4/30/07, David Goldsmith <David.L.Goldsmith@noaa.gov> wrote:
>
>
> > (hint what is arctan(0+1j)?)
> >
> Well, at the risk of embarrassing myself, using arctan(x+iy) = I get:
>
> arctan(0+1i) = -i*log((0+i*1)/sqrt(0^2 + 1^2)) = -i*log(i/1) = -i*log(i)
> = -i*log(exp(i*pi/2)) = -i*i*pi/2 = pi/2...
>
> Is there some reason I'm forgetting (e.g., a branch cut convention or
> something) why this is wrong?
Oops. It may well be OK, I answered too fast (I'd explain my thinking, but
ti would be embarassing). However, I believe atan works in general for
complex numbers but it may well have a problem for this specific case.
I should look at this more closely though since the behaviour near zero does
seem a little odd. No time right now, but maybe later today.
DG
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--
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tim.hochberg@ieee.org
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