[Numpy-discussion] How do I test if an array contains NaN ?

[Christopher Barker]

Fernando Perez wrote:

> It's probably worth mentioning that IPython has (thanks to a user
> contributed implementation) search capabilities besides tab completion

very handy.

And if you're an idiot like me that for some unknown reason still does 
not use ipython, you can always do:

for i in dir(N):
     if "nan" in i: print i

 >>> import numpy as N
 >>> for i in dir(N):
...     if "nan" in i: print i
...
isnan
nan
nan_to_num
nanargmax
nanargmin
nanmax
nanmin
nansum

-Chris


-- 
Christopher Barker, Ph.D.
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