[Numpy-discussion] Fwd: Advanced selection, duplicate indices, and augmented assignment
tim.hochberg at ieee.org
Sat Jan 6 21:25:08 CST 2007
On 1/6/07, Robert Kern <robert.kern at gmail.com> wrote:
> Sean R. Lynch wrote:
> >>>> x = zeros((3,))
> >>>> x[array([0, 1, 1])] += array([1, 1, 1])
> >>>> x
> > array([ 1., 1., 0.])
> > If this worked the way I was hoping, the output would be [1 2 0] because
> > it would add to element 1 twice due to its duplication in the advanced
> > selection array.
> > Is the current behavior intentional or is it an accident of
> > implementation?
> It is an unavoidable consequence of the way Python interprets that code
> and the
> way numpy arrays are fundamentally implemented. See Travis Oliphant's, Tim
> Hochberg's and my posts in the thread "Histograms via indirect index
> arrays" for
> more details.
Do we have to revisit that thread? I seem to recall it getting kind of
cranky. To avoid reliving that, I will attempt dredge up the relevant issue:
"a[indx]+=b" should be the same as "a[indx]=a[indx]+b". All else follow from
that. If staring at that for a while doesn't enlighten you, then you will
have to read that thread.
[ I suspect that in theory we could make the += form behave as you expect,
but that would break the identity above, which would confuse a bunch of
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