[Numpy-discussion] How do I test if an array contains NaN ?
bthom at cs.hmc.edu
Thu Jan 11 21:07:13 CST 2007
> It's probably worth mentioning that IPython has (thanks to a user
> contributed implementation) search capabilities besides tab completion
> (which requires you to at least know the start of the string you
> In : N.*nan*?
this thing can be used even more slickly:
N.[a-z]*? prints only the "non private" stuff.
i'm starting to find this greatly speeds up my development cycle.
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