[Numpy-discussion] NumPy/SciPy LAPACK version
Charles R Harris
Mon Jul 16 12:00:45 CDT 2007
On 7/16/07, Robert Kern <email@example.com> wrote:
> Kevin Jacobs <firstname.lastname@example.org> wrote:
> > Mea culpa on the msqrt example, however I still think it is wrong to get
> > a complex square-root back when a real valued result is expected and
> No, in floating point you accumulate error. Those 1e-22j's are part of the
> actual result. Some systems like MATLAB implicitly silent such small
> components; we don't.
The problem is that the given matrix has a conditon number of about 10**17
and is almost singular. A singular value decomposition works fine, but
apparently the sqrtm call suffers from roundoff and takes the sqrt of a
negative number. Sqrtm returns real results in better conditioned cases.
In : sqrtm(eye(2))
array([[ 1., 0.],
[ 0., 1.]])
Perhaps we aren't using the best method here.
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