# [Numpy-discussion] histogram using decending range -- what do the results mean?

Robert Kern robert.kern@gmail....
Fri Oct 5 17:04:47 CDT 2007

```Mark.Miller wrote:
> Check how you're implementing the histogram function with respect to
> that range statement.  It seems to make a difference, desirable or not.
>
>  >>> import numpy
>  >>> numpy.__version__
> '1.0.4.dev3982'
>  >>> A = numpy.array([1, 2, 3, 4, 5, 6, 5, 4, 5, 4, 3, 2, 1])
>  >>> (x, y) = numpy.histogram(A, range(0, 7))
>  >>> x
> array([0, 2, 2, 2, 3, 3, 1])
>  >>> y
> [0, 1, 2, 3, 4, 5, 6]
>  >>>
>  >>> (x, y) = numpy.histogram(A, range=(0, 7))
>  >>> x
> array([0, 2, 2, 0, 2, 3, 0, 3, 1, 0])
>  >>> y
> array([ 0. ,  0.7,  1.4,  2.1,  2.8,  3.5,  4.2,  4.9,  5.6,  6.3])

Please check the signature of numpy.histogram(). The two aren't intended to be
the same. The range argument has nothing to do with the builtin range() function.

>  >>>
>  >>>
>  >>> (x, y) = numpy.histogram(A, range(7,0))
>  >>> x
> array([], dtype=int32)
>  >>> y
> []
>  >>>
>
> Note that in the last case, the histogram function isn't returning
> anything for a descending range.
>
> Also notice that you're overwriting a python function with the way
> you're assigning things....

No, he's not. "range" is a keyword argument to histogram(). He's using it correctly.

--
Robert Kern

"I have come to believe that the whole world is an enigma, a harmless enigma