[Numpy-discussion] Using normal()
Joris De Ridder
Joris.DeRidder@ster.kuleuven...
Thu Apr 24 13:16:48 CDT 2008
On 24 Apr 2008, at 19:26, Rich Shepard wrote:
>> norm = 1 / (scale * sqrt(2 * pi))
>> y = norm * exp(-power((x - loc), 2) / (2 * scale**2))
>
> Can do. So, scale would equate to width and loc to center, yes?
Scale is half the width between the inflection points, mind the factor
of 2.
J.
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