[Numpy-discussion] unique1d returning indices
Robert Cimrman
cimrman3@ntc.zcu...
Wed Aug 6 07:52:38 CDT 2008
Hi,
due to popular demand, I have updated unique1d() to optionally return
both kinds of indices:
In [3]: b, i, j = nm.unique1d( a, return_index=True, return_inverse=True )
In [4]: a
Out[4]: array([1, 1, 8, 3, 3, 5, 4])
In [6]: b
Out[6]: array([1, 3, 4, 5, 8])
In [7]: a[i]
Out[7]: array([1, 3, 4, 5, 8])
In [8]: b[j]
Out[8]: array([1, 1, 8, 3, 3, 5, 4])
In [9]: a
Out[9]: array([1, 1, 8, 3, 3, 5, 4])
Could someone needing this try the attached code? If it is ok I will
update the tests, the docstring and commit it.
Note also that the order of outputs has changed (previously unique1d()
returned (i, b) for return_index=True).
cheers,
r.
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