[Numpy-discussion] min() of array containing NaN

Charles R Harris charlesr.harris@gmail....
Tue Aug 12 19:28:22 CDT 2008


On Tue, Aug 12, 2008 at 5:13 PM, Andrew Dalke <dalke@dalkescientific.com>wrote:

> On Aug 12, 2008, at 9:54 AM, Anne Archibald wrote:
> > Er, is this actually a bug? I would instead consider the fact that
> > np.min([]) raises an exception a bug of sorts - the identity of min is
> > inf.
>
<snip>


>
> Personally, I expect that if my array 'x' has a NaN then
> min(x) must be a NaN.
>

I suppose you could use

min(a,b) = (abs(a - b) + a + b)/2

which would have that effect.

Chuck
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