[Numpy-discussion] numpy.sign(numpy.nan)?????

Robert Kern robert.kern@gmail....
Fri May 16 14:29:36 CDT 2008


On Fri, May 16, 2008 at 2:27 PM, Keith Goodman <kwgoodman@gmail.com> wrote:
> On Fri, May 16, 2008 at 11:23 AM, Robert Kern <robert.kern@gmail.com> wrote:
>> On Fri, May 16, 2008 at 11:23 AM, Stuart Brorson <sdb@cloud9.net> wrote:
>>> In [66]: numpy.sign(numpy.nan)
>>> Out[66]: 0.0
>>>
>>> IMO, the output should be NaN, not zero.
>>
>> You're probably right. I would like to see what other systems do
>> before changing it, though.
>
> octave:1> sign(nan)
> ans = NaN

Works for me.

-- 
Robert Kern

"I have come to believe that the whole world is an enigma, a harmless
enigma that is made terrible by our own mad attempt to interpret it as
though it had an underlying truth."
 -- Umberto Eco


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