[Numpy-discussion] distance_matrix: how to speed up?
Emanuele Olivetti
emanuele@relativita....
Wed May 21 07:39:17 CDT 2008
Dear all,
I need to speed up this function (a little example follows):
------
import numpy as N
def distance_matrix(data1,data2,weights):
rows = data1.shape[0]
columns = data2.shape[0]
dm = N.zeros((rows,columns))
for i in range(rows):
for j in range(columns):
dm[i,j] = ((data1[i,:]-data2[j,:])**2*weights).sum()
pass
pass
return dm
size1 = 4
size2 = 3
dimensions = 2
data1 = N.random.rand(size1,dimensions)
data2 = N.random.rand(size2,dimensions)
weights = N.random.rand(dimensions)
dm = distance_matrix(data1,data2,weights)
print dm
------------------
The distance_matrix function computes the weighted (squared) euclidean
distances between each pair of vectors from two sets (data1, data2).
The previous naive algorithm is extremely slow for my standard use,
i.e., when size1 and size2 are in the order of 1000 or more. It can be
improved using N.subtract.outer:
def distance_matrix_faster(data1,data2,weights):
rows = data1.shape[0]
columns = data2.shape[0]
dm = N.zeros((rows,columns))
for i in range(data1.shape[1]):
dm += N.subtract.outer(data1[:,i],data2[:,i])**2*weights[i]
pass
return dm
This algorithm becomes slow when dimensions (i.e., data1.shape[1]) is
big (i.e., >1000), due to the Python loop. In order to speed it up, I guess
that N.subtract.outer could be used on the full matrices instead of one
column at a time. But then there is a memory issue: 'outer' allocates
too much memory since it stores all possible combinations along all
dimensions. This is clearly unnecessary.
Is there a NumPy way to avoid all Python loops and without wasting
too much memory? As a comparison I coded the same algorithm in
C through weave (inline): it is _much_ faster and requires just
the memory to store the result. But I'd prefer not using C or weave
if possible.
Thanks in advance for any help,
Emanuele
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