# [Numpy-discussion] Any and all NaNs

Keith Goodman kwgoodman@gmail....
Fri May 23 12:22:09 CDT 2008

```On Fri, May 23, 2008 at 10:16 AM, Keith Goodman <kwgoodman@gmail.com> wrote:
> I'm writing unit tests for a module that contains matrices. I was
> surprised that these are True:
>
>>> import numpy.matlib as mp
>>> x = mp.matrix([[mp.nan]])
>>> x.any()
>   True
>>> x.all()
>   True
>
> My use case is (x == y).all() where x and y are the same matrix except
> that x contains one NaN. Certianly x and y are not equal.
>
>>> x = mp.asmatrix(range(4)).reshape(2,2)
>>> y = mp.asmatrix(range(4)).reshape(2,2)
>>> x[0,0] = mp.nan
>>> (x == y).all()
>   True

Sorry. Ignore the last example. I used integers. Here's the example with floats:

>> x = 1.0 * mp.asmatrix(range(4)).reshape(2,2)
>> y = 1.0 * mp.asmatrix(range(4)).reshape(2,2)
>> x[0,0] = mp.nan
>> x

matrix([[ NaN,   1.],
[  2.,   3.]])
>> (x == y).all()
False

But the first example

>> x = mp.matrix([[mp.nan]])
>> x
matrix([[ NaN]])
>> x.all()
True
>> x.any()
True

is still surprising.
```

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