[Numpy-discussion] Any and all NaNs
Fri May 23 13:44:14 CDT 2008
On Fri, May 23, 2008 at 12:22 PM, Keith Goodman <firstname.lastname@example.org> wrote:
> But the first example
>>> x = mp.matrix([[mp.nan]])
> matrix([[ NaN]])
> is still surprising.
On non-boolean arrays, .all() and .any() check each element to see if
it is not equal to 0. NaN != 0. Returning False would be just as
wrong. If there were a Maybe in addition to True and False, then
perhaps that would be worth changing, but I don't see a reason to
change the rule as it is.
"I have come to believe that the whole world is an enigma, a harmless
enigma that is made terrible by our own mad attempt to interpret it as
though it had an underlying truth."
-- Umberto Eco
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