[Numpy-discussion] linalg.norm along axis?

Nicolas Pinto pinto@mit....
Wed Feb 18 22:12:09 CST 2009


Grissiom,

Using the following doesn't require any loop:

In [9]: sqrt((a**2.).sum(1))
Out[9]: array([  5.,  10.])

Best,


On Wed, Feb 18, 2009 at 10:23 PM, Grissiom <chaos.proton@gmail.com> wrote:

> Hi all,
>
> Is there any possibility to calculate norm along axis? For example:
>
> a = np.array((
> (3,4),
> (6,8)))
>
> And I want to get:
> array([5.0, 10.0])
>
> I currently use a for loop to achieve this, Is there any more elegant way
> to do this?
>
> --
> Cheers,
> Grissiom
>
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>
>


-- 
Nicolas Pinto
Ph.D. Candidate, Brain & Computer Sciences
Massachusetts Institute of Technology, USA
http://web.mit.edu/pinto
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