[Numpy-discussion] double-precision sqrt?
Sat Oct 17 17:03:08 CDT 2009
Hi again, I apologize, the mistake was entirely my own. Sqrt's do the
On Sat, Oct 17, 2009 at 12:17 PM, Adam Ginsburg
> My code is actually wrong.... but I still have the problem I've
> identified that sqrt is leading to precision errors. Sorry about the
> earlier mistake.
> On Sat, Oct 17, 2009 at 12:08 PM, Adam Ginsburg
> <email@example.com> wrote:
>> # 1.0170174646791199
>> f=lambda x: x**2-float64(1.034324523462345)**2
> should be
> f=lambda x: x**2-float64(1.034324523462345)
> so the code I sent was not a legitimate test.
More information about the NumPy-Discussion