[Numpy-discussion] Matrix operation.

gerardob gberbeglia@gmail....
Fri Apr 2 09:35:44 CDT 2010


Let A be a square matrix of 0's and 1's, and let X be a one dimesional
vector.
The length of X is equal to the number of 1's that A has.
I would like to produce a new matrix B by traversing the matrix A row by row
and:
1- whenever i find a 0, set B in that position to zero.
2- whenever i find a 1, set B in that position with the ith value of X
(where i represents the ith time i found a 1).

Example.
input:
A=[[1,1,0],
[1,0,0],
[0,0,1]]

X=[2,9,10,3]

Output:
B =[[2,9,0],
   [10,0,0],
   [0,0,3]]
 
Which is an efficient way to accomplish this using numpy?
 
Thanks.
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