[Numpy-discussion] numpy.concatenate slower than slice copying
Chris Colbert
sccolbert@gmail....
Tue Aug 17 16:42:54 CDT 2010
Yes, concatenate is doing other work under the covers. In short, in supports
concatenating a list of arbitrary python sequences into an array and does
checking on each element of the tuple to ensure it is valid to concatenate.
On Tue, Aug 17, 2010 at 9:03 AM, Zbyszek Szmek <zbyszek@in.waw.pl> wrote:
> Hi,
> this is a problem which came up when trying to replace a hand-written
> array concatenation with a call to numpy.vstack:
> for some array sizes,
>
> numpy.vstack(data)
>
> runs > 20% longer than a loop like
>
> alldata = numpy.empty((tlen, dim))
> for x in data:
> step = x.shape[0]
> alldata[pos:pos+step] = x
> pos += step
>
> (example script attached)
>
> $ python del_cum3.py numpy 10000 10000 1 10
> problem size: (10000x10000) x 1 = 10^8
> 0.816s <------------------------------- numpy.concatentate of 10 arrays
> 10000x10000
>
> $ python del_cum3.py concat 10000 10000 1 10
> problem size: (10000x10000) x 1 = 10^8
> 0.642s <------------------------------- slice manipulation giving the same
> result
>
> When the array size is reduced to 100x100 or so, the computation time goes
> to 0,
> so it seems that the dtype and dimension checking is negligible.
> Does numpy.concatenate do some extra work?
>
> Thanks for any pointers,
> Zbyszek
>
> PS. Architecture is amd64.
> python2.6, numpy 1.3.0
> or
> python3.1, numpy 2.0.0.dev / trunk@8510
> give the same result.
>
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>
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