[Numpy-discussion] np.choose() question
Tue Jun 8 12:23:22 CDT 2010
Not pretty, but it works:
array([100, 101, 102, 103, 104])
On Tue, Jun 8, 2010 at 10:09 AM, Gökhan Sever <firstname.lastname@example.org> wrote:
> On Tue, Jun 8, 2010 at 11:24 AM, Andreas Hilboll <email@example.com> wrote:
>> Hi there,
>> I have a problem, which I'm sure can somehow be solved using np.choose()
>> - but I cannot figure out how :(
>> I have an array idx, which holds int values and has a 2d shape. All
>> values inside idx are 0 <= idx < n. And I have a second array times,
>> which is 1d, with times.shape = (n,).
>> Out of these two arrays I now want to create a 2d array having the same
>> shape as idx, and holding the values contained in times, as indexed by
>> A simple np.choose(idx,times) does not work (error "Need between 2 and
>> (32) array objects (inclusive).").
>> idx = [[4,2],[3,1]]
>> times = [100,101,102,103,104]
>> From these two I want to create an array
>> result = [[104,102],[103,101]]
>> How can this be done?
>> Thanks a lot for your insight!
>> NumPy-Discussion mailing list
> Here is a non numpy.choose solution:
> newtimes = [times[idx[x][y]] for x in range(2) for y in range(2)]
> array([[104, 102],
> [103, 101]])
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