[Numpy-discussion] Simple problem. Is it possible without a loop?

[Robert Elsner]

There might be an easier way to accomplish that

y = x[(x[1:]-x[:-1]) >= delta]

cheers

Am Mittwoch, den 09.06.2010, 10:00 +0200 schrieb "V. Armando Solé":
> Well, this seems to be quite close to what I need
> 
> y = numpy.cumsum((x[1:]-x[:-1])/delta).astype(numpy.int)
> i1 = numpy.nonzero(y[1:] > y[:-1])
> y = numpy.take(x, i1)
> 
> Sorry for the time taken!
> 
> Best regards,
> 
> Armando
> 
> V. Armando Solé wrote:
> > Hello,
> >
> > I am trying to solve a simple problem that becomes complex if I try to 
> > avoid looping.
> >
> > Let's say I have a 1D array, x,  where x[i] <= x[i+1]
> >
> > Given a certain value delta, I would like to get a subset of x, named y, 
> > where (y[i+1] - y[i]) >= delta
> >
> > In a non-optimized and trivial way, the operation I would like to do is:
> >
> > y=[x[0]]
> > for value in x:
> >     if (y[-1] -value) < delta:
> >        y.append(value)
> > y=numpy.array(y)
> >
> > Any hint?
> >
> > Best regards,
> >
> > Armando
> >
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> >
> >   
> 
> 
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