[Numpy-discussion] Simplified question on tensordot
Fri Sep 3 07:28:19 CDT 2010
Josef and Pauli,
Wow, you guys rock! I'm amazed you could pull that out so quickly.
I thank you, and PyQuante thanks you (hopefully this will make for faster
density functional theory grids).
On Fri, Sep 3, 2010 at 5:59 AM, <firstname.lastname@example.org> wrote:
> On Fri, Sep 3, 2010 at 7:48 AM, Rick Muller <email@example.com> wrote:
> > Sorry for the rapid repost, but I thought of a much easier way to ask the
> > question I asked a few minutes ago.
> > I have two matrices, A and B, both of which are n x m. n is big
> > and m is small (~10).
> > I want to take the product AB such that I get a length-n vector, as in:
> >>>> AB = zeros(n,'d')
> >>>> for i in xrange(n):
> >>>> AB[i] = dot(A[i,:],B[i,:])
> Isn't this just (A*B).sum(1) ?
> > only I don't want the for-loop. The various things I've tried with dot
> > tensordot inevitably give me a n x n matrix, which isn't what I want. Can
> > anyone help me find an easier way to do this?
> > --
> > Rick Muller
> > firstname.lastname@example.org
> > _______________________________________________
> > NumPy-Discussion mailing list
> > NumPy-Discussion@scipy.org
> > http://mail.scipy.org/mailman/listinfo/numpy-discussion
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