[Numpy-discussion] Identifying Colinear Columns of a Matrix

Charles R Harris charlesr.harris@gmail....
Fri Aug 26 13:04:07 CDT 2011


On Fri, Aug 26, 2011 at 11:41 AM, Mark Janikas <mjanikas@esri.com> wrote:

> I wonder if my last statement is essentially the only answer... which I
> wanted to avoid...
>
> Should I just use combinations of the columns and try and construct the
> corrcoef() (then ID whether NaNs are present), or use the condition number
> to ID the singularity?  I just wanted to avoid the whole k! algorithm.
>
> MJ
>
> -----Original Message-----
> From: numpy-discussion-bounces@scipy.org [mailto:
> numpy-discussion-bounces@scipy.org] On Behalf Of Mark Janikas
> Sent: Friday, August 26, 2011 10:35 AM
> To: Discussion of Numerical Python
> Subject: Re: [Numpy-discussion] Identifying Colinear Columns of a Matrix
>
> I actually use the VIF when the design matrix can be inverted.... I do it
> the quick and dirty way as opposed to the step regression:
>
> 1. Calc the correlation coefficient of the matrix (w/o the intercept)
> 2. Return the diagonal of the inversion of the correlation matrix in step
> 1.
>
> Again, the problem lies in the multiple column relationship... I wouldn't
> be able to run sub regressions at all when the columns are perfectly
> collinear.
>
> MJ
>
> -----Original Message-----
> From: numpy-discussion-bounces@scipy.org [mailto:
> numpy-discussion-bounces@scipy.org] On Behalf Of Skipper Seabold
> Sent: Friday, August 26, 2011 10:28 AM
> To: Discussion of Numerical Python
> Subject: Re: [Numpy-discussion] Identifying Colinear Columns of a Matrix
>
> On Fri, Aug 26, 2011 at 1:10 PM, Mark Janikas <mjanikas@esri.com> wrote:
> > Hello All,
> >
> >
> >
> > I am trying to identify columns of a matrix that are perfectly collinear.
> > It is not that difficult to identify when two columns are identical are
> have
> > zero variance, but I do not know how to ID when the culprit is of a
> higher
> > order. i.e. columns 1 + 2 + 3 = column 4.  NUM.corrcoef(matrix.T) will
> > return NaNs when the matrix is singular, and LA.cond(matrix.T) will
> provide
> > a very large condition number.. But they do not tell me which columns are
> > causing the problem.   For example:
> >
> >
> >
> > zt = numpy. array([[ 1.  ,  1.  ,  1.  ,  1.  ,  1.  ],
> >
> >                            [ 0.25,  0.1 ,  0.2 ,  0.25,  0.5 ],
> >
> >                            [ 0.75,  0.9 ,  0.8 ,  0.75,  0.5 ],
> >
> >                            [ 3.  ,  8.  ,  0.  ,  5.  ,  0.  ]])
> >
> >
> >
> > How can I identify that columns 0,1,2 are the issue because: column 1 +
> > column 2 = column 0?
> >
> >
> >
> > Any input would be greatly appreciated.  Thanks much,
> >
>
> The way that I know to do this in a regression context for (near
> perfect) multicollinearity is VIF. It's long been on my todo list for
> statsmodels.
>
> http://en.wikipedia.org/wiki/Variance_inflation_factor
>
> Maybe there are other ways with decompositions. I'd be happy to hear about
> them.
>
> Please post back if you write any code to do this.
>
>
Why not svd?

In [13]: u,d,v = svd(zt)

In [14]: d
Out[14]:
array([  1.01307066e+01,   1.87795095e+00,   3.03454566e-01,
         3.29253945e-16])

In [15]: u[:,3]
Out[15]: array([ 0.57735027, -0.57735027, -0.57735027,  0.        ])

In [16]: dot(u[:,3], zt)
Out[16]:
array([ -7.77156117e-16,  -6.66133815e-16,  -7.21644966e-16,
        -7.77156117e-16,  -8.88178420e-16])

Chuck
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