[Numpy-discussion] A bit of advice?
Thu Jun 23 08:03:46 CDT 2011
On Thu, Jun 23, 2011 at 8:20 AM, Neal Becker <email@example.com> wrote:
> Olivier Delalleau wrote:
>> What about :
>> dict((k, [e for e in arr if (e['x0'], e['x1']) == k]) for k in cases)
> Not bad! Thanks!
> BTW, is there an easier way to get the unique keys, then this:
> cases = tuple (set (tuple((e['a'],e['b'])) for e in u))
I think you can just combine these 2
experiments = defaultdict() #syntax ?
for i, e in enumerate(arr):
#experiments[tuple((e['a'],e['b']))].append(y['c']) #or just
(just typed not checked)
>> (note: it is inefficient written this way though)
>> -=- Olivier
>> 2011/6/23 Neal Becker <firstname.lastname@example.org>
>>> I have a set of experiments that I want to plot. There will be many plots.
>>> Each will show different test conditions.
>>> Suppose I put each of the test conditions and results into a recarray. The
>>> recarray could be:
>>> arr = np.empty ((#experiments,), dtype=[('x0',int), ('x1',int), ('y0',int)]
>>> where x0,x1 are 2 test conditions, and y0 is a result.
>>> First I want to group the plots such according to the test conditions. So,
>>> want to first find what all the combinations of test conditions are.
>>> Dunno if there is anything simpler than:
>>> cases = tuple (set ((e['x0'], e['x1'])) for e in arr)
>>> Next, need to select all those experiments which match each of these cases.
>>> I know of no easy way.
>>> Any suggestions? Perhaps I should look again at pytables?
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