[Numpy-discussion] numpy.int32 is not subclass of int, but numpy.int64 is
Tue Nov 15 08:48:32 CST 2011
From: firstname.lastname@example.org [mailto:email@example.com] On Behalf Of Olivier Delalleau
Sent: Tuesday, November 15, 2011 7:03 AM
To: Discussion of Numerical Python
Subject: Re: [Numpy-discussion] numpy.int32 is not subclass of int, but numpy.int64 is
2011/11/14 Robert Kern <firstname.lastname@example.org<mailto:email@example.com>>
On Mon, Nov 14, 2011 at 20:18, MACKEITH Andrew <Andrew.MACKEITH@3ds.com<mailto:Andrew.MACKEITH@3ds.com>> wrote:
> Could someone explain this?
> An instance of numpy.int32 is not an instance of int or numpy.int<http://numpy.int>.
> An instance of numpy.int64 is an instance of int and numpy.int<http://numpy.int>.
> I don't know if it is a bug in my linux build.
>>>> import sys
>>>> import platform
>>>> print platform.platform()
This is expected on a 64-bit platform. Note that numpy.int<http://numpy.int> is just an
alias for the builtin int type for backwards compatibility with an
earlier version of numpy. We could probably remove it, since it seems
to be causing more confusion than not.
Anyways, we subclass the appropriately sized integer scalar type from
Python's int type depending on the platform. So on a platform where
Python's int type is 64-bits, numpy.int64 will include int in its
inheritance tree. On platforms where the Python int type is 32-bit,
numpy.int32 will include it instead.
I'll just add that there is a numpy.integer class that is parent of both numpy.int32 and numpy.int64 (see http://docs.scipy.org/doc/numpy/reference/arrays.scalars.html). It's not a parent of numpy.int<http://numpy.int> though, since as said above, numpy.int<http://numpy.int> is an alias to the builtin int.
Thanks you for the information. numpy.integer is what I was looking for.
Is there an equivalent base class for float types?
Do you know where these are documented?
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