[Numpy-discussion] Large numbers into float128
Charles R Harris
Sat Oct 29 22:02:37 CDT 2011
On Sat, Oct 29, 2011 at 8:49 PM, Matthew Brett <email@example.com>wrote:
> On Sat, Oct 29, 2011 at 3:55 PM, Matthew Brett <firstname.lastname@example.org>
> > Hi,
> > Can anyone think of a good way to set a float128 value to an
> > arbitrarily large number?
> > As in
> > v = int_to_float128(some_value)
> > ?
> > I'm trying things like
> > v = np.float128(2**64+2)
> > but, because (in other threads) the float128 seems to be going through
> > float64 on assignment, this loses precision, so although 2**64+2 is
> > representable in float128, in fact I get:
> > In : np.float128(2**64+2)
> > Out: 18446744073709551616.0
> > In : 2**64+2
> > Out: 18446744073709551618L
> > So - can anyone think of another way to assign values to float128 that
> > will keep the precision?
> To answer my own question - I found an unpleasant way of doing this.
> Basically it is this:
> def int_to_float128(val):
> f64 = np.float64(val)
> res = val - int(f64)
> return np.float128(f64) + np.float128(res)
> Used in various places here:
It might be useful to look into mpmath. I didn't see any way to export mp
values into long double, but they do offer a number of resources for working
with arbitrary precision. We could maybe even borrow some of their stuff for
parsing values from strings
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