[Numpy-discussion] f2py with int8
Paul Anton Letnes
paul.anton.letnes@gmail....
Tue Apr 17 00:53:03 CDT 2012
Hi,
this probably does not help with your problem. However, I would recommend changing your fortran code to:
subroutine print_bit_array(bits)
use iso_fortran_env
integer(kind=int8),intent(in),dimension(:)::bits
print*,'bits = ',bits
end subroutine print_bit_array
In that way you could print shape(bits) to verify that you are getting an array of the size you are expecting. Also, you could compile with -fbounds-check (gfortran) or a similar flag for some extra debugging facilities.
To get better help with your issues, I would recommend also posting your call to the fortran routine, and the compilation command used (f2py -m myfile.f90 -flags....).
Cheers
Paul
On 17. apr. 2012, at 07:32, John Mitchell wrote:
> Hi,
>
> I am using f2py to pass a numpy array of type numpy.int8 to fortran. It seems like I am misunderstanding something because I just can't make it work.
>
> Here is what I am doing.
>
> PYTHON
> b=numpy.array(numpy.zeros(shape=(10,),dtype=numpy.int8),order='F')
> b[0]=1
> b[2]=1
> b[3]=1
> b
> array([1, 0, 1, 1, 0, 0, 0, 0, 0, 0], dtype=int8)
>
>
>
> FORTRAN
> subroutine print_bit_array(bits,n)
> use iso_fortran_env
> integer,intent(in)::n
> integer(kind=int8),intent(in),dimension(n)::bits
> print*,'bits = ',bits
> end subroutine print_bit_array
>
>
> RESULT when calling fortran from python
> bits = 1 0 0 0 0 0 0 0 1 0
>
> Any Ideas?
> thanks,
> John
>
>
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