[Numpy-discussion] numpy.percentile multiple arrays
questions anon
questions.anon@gmail....
Tue Jan 24 21:49:46 CST 2012
thanks for your responses,
because of the size of the dataset I will still end up with the memory
error if I calculate the median for each file, additionally the files are
not all the same size. I believe this memory problem will still arise with
the cumulative distribution calculation and not sure I understand how to
write the second suggestion about the iterative approach but will have a go.
Thanks again
On Wed, Jan 25, 2012 at 1:26 PM, Brett Olsen <brett.olsen@gmail.com> wrote:
> On Tue, Jan 24, 2012 at 6:22 PM, questions anon
> <questions.anon@gmail.com> wrote:
> > I need some help understanding how to loop through many arrays to
> calculate
> > the 95th percentile.
> > I can easily do this by using numpy.concatenate to make one big array and
> > then finding the 95th percentile using numpy.percentile but this causes a
> > memory error when I want to run this on 100's of netcdf files (see code
> > below).
> > Any alternative methods will be greatly appreciated.
> >
> >
> > all_TSFC=[]
> > for (path, dirs, files) in os.walk(MainFolder):
> > for dir in dirs:
> > print dir
> > path=path+'/'
> > for ncfile in files:
> > if ncfile[-3:]=='.nc':
> > print "dealing with ncfiles:", ncfile
> > ncfile=os.path.join(path,ncfile)
> > ncfile=Dataset(ncfile, 'r+', 'NETCDF4')
> > TSFC=ncfile.variables['T_SFC'][:]
> > ncfile.close()
> > all_TSFC.append(TSFC)
> >
> > big_array=N.ma.concatenate(all_TSFC)
> > Percentile95th=N.percentile(big_array, 95, axis=0)
>
> If the range of your data is known and limited (i.e., you have a
> comparatively small number of possible values, but a number of repeats
> of each value) then you could do this by keeping a running cumulative
> distribution function as you go through each of your files. For each
> file, calculate a cumulative distribution function --- at each
> possible value, record the fraction of that population strictly less
> than that value --- and then it's straightforward to combine the
> cumulative distribution functions from two separate files:
> cumdist_both = (cumdist1 * N1 + cumdist2 * N2) / (N1 + N2)
>
> Then once you've gone through all the files, look for the value where
> your cumulative distribution function is equal to 0.95. If your data
> isn't structured with repeated values, though, this won't work,
> because your cumulative distribution function will become too big to
> hold into memory. In that case, what I would probably do would be an
> iterative approach: make an approximation to the exact function by
> removing some fraction of the possible values, which will provide a
> limited range for the exact percentile you want, and then walk through
> the files again calculating the function more exactly within the
> limited range, repeating until you have the value to the desired
> precision.
>
> ~Brett
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