[Numpy-discussion] Re place array values

[Derek Ashley Thomas]

Hi,
I'm completely new to this list (and fairly new to numpy in general), but I
was wondering if you tried multiplying the bool array and the original
array.

Try:
x=array([[0,1,2],[3,4,5],[6,7,8]])

if rank(x) <= 1
  dot(x>=1, x)
else
  (x>=1)*x

This will give you a completely numerical array of the same structure, but
all numbers less than 1 will be zero fo easy handling. Is this what you're
trying to accomplish?

--
Derek



On Thu, Mar 15, 2012 at 08:35, jonasr <jonas.ruebsam@web.de> wrote:

>
> Hello,
>
> my problem is that i want to remove some small numbers of an 2d array,
> for example if i want to sort out all numbers smaller then 1 of an array i
> get
>
> x=[[0,1,2],[3,4,5][6,7,8]]
>
> c=x>=1
>
> In [213]: c
> Out[213]:
> array([[False,  True,  True],
>       [ True,  True,  True],
>       [ True,  True,  True]], dtype=bool)
>
> In [214]: x[c]
> Out[214]: array([1, 2, 3, 4, 5, 6, 7, 8])
>
> the problem ist that i now have a 1d array, is there any possibility to
> keep the 2d structure ?
>
> greets jonas
> --
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