[Numpy-discussion] float96 on windows32 is float64?
Thu Mar 15 23:33:49 CDT 2012
I just happened to have an xp64 VM running:
My version of numpy (1.6.1) does not have float128 (see more below what I
get in ipython session).
If you need to test something else please let me know.
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In : import numpy as np
In : np.__version__
In : np.flo
np.float np.float32 np.float_ np.floor
np.float16 np.float64 np.floating np.floor_divide
In : np.flo
On Thu, Mar 15, 2012 at 11:25 PM, Matthew Brett <email@example.com>wrote:
> On Thu, Mar 15, 2012 at 9:17 PM, David Cournapeau <firstname.lastname@example.org>
> > On Thu, Mar 15, 2012 at 11:10 PM, Matthew Brett <email@example.com
> > wrote:
> >> Hi,
> >> Am I right in thinking that float96 on windows 32 bit is a float64
> >> padded to 96 bits?
> > Yes
> >> If so, is it useful?
> > Yes: this is what allows you to use dtype to parse complex binary files
> > directly in numpy without having to care so much about those details. And
> > that's how it is defined on windows in any case (C standard only forces
> > to have sizeof(long double) >= sizeof(double)).
> I propose then to rename this one to float64_96 .
> The nexp value in finfo(np.float96) is incorrect I believe, I'll make
> a ticket for it.
> >> Has anyone got a windows64
> >> box to check float128 ?
> > Too lazy to check on my vm, but I am pretty sure it is 16 bytes on
> > 64.
> Should you have time to do that, could you confirm it's also a padded
> float64 and that nexp is still (incorrectly) 15? That would be a
> great help,
> NumPy-Discussion mailing list
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