[SciPy-dev] fast gaussian filtering
Fri Dec 19 12:51:30 CST 2008
> Yes, for kernels smaller than 10 or so it will be faster. But a
> is actually not of finite size. So a finite sized Gaussian is
> actually a
> misnomer; it should be a truncated Gaussian. The recursion does not
> truncate the Gaussian kernel (but at some point the impulse response
> will be so small that it falls into the range of rounding error).
Aah, cool -- that's good to know. I'll definitely keep your
implementation handy. It would definitely be great up on the cookbook!
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