[SciPy-dev] numpy.broadcast

David Goldsmith d_l_goldsmith@yahoo....
Wed Aug 5 15:40:01 CDT 2009


--- On Wed, 8/5/09, David Goldsmith <d_l_goldsmith@yahoo.com> wrote:

> > It is necessarily == D. Broadcasting is associative. 
> > The
> > (x*y*z).shape
> > == (x*(y*z)).shape == ((x*y)*z).shape.

Um:

>>> x = np.array((1, 2, 3))
>>> y = np.array([[4], [5], [6]])
>>> z = x * y
>>> x; y; z
array([1, 2, 3])
array([[4],
       [5],
       [6]])
array([[ 4,  8, 12],
       [ 5, 10, 15],
       [ 6, 12, 18]])
>>> B = np.broadcast
>>> X = B(x, y, z)
>>> Y = B(x, B(y, z))
>>> Z = B(B(x, y), z)
>>> X.numiter, Y.numiter, Z.numiter
(3, 2, 2)
>>> X.nd, Y.nd, Z.nd
(2, 1, 2)
>>> X.shape, Y.shape, Z.shape
((3, 3), (3,), (3, 3))

Am I doing something wrong?

DG


      


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