[SciPy-user] Replacing elements in matrix
steve schmerler
elcorto at gmx.net
Tue Apr 26 10:31:48 CDT 2005
Dimitri D'Or wrote:
> Hello,
>
> I come from the Matlab world and I'm used to write operations such as:
> A[indexi,indexj]=A[indexi,indexj]+B
> where A is a n by n matrix, indexi is i by 1 vector, indexj is a j by 1
> vector and B is a i by j matrix.
>
> With this operation, some of the elements of A are replaced by their
> original value augmented by some value coming from B.
>
> for example, take
>
> A=array([[1,5,7,8,2],[5,3,4,6,7],[9,4,6,7,2],[0,2,0,3,4]])
> indexi=array([0,2])
> indexj=array([1,2,4])
> B=array([[10,20,30],[100,200,300]])
>
> With this, Matlab results would be
> A[indexi,indexj]=array([[5, 7, 2],[4, 6, 2]])
> and
> A[indexi,indexj]=A[indexi,indexj]+B yields
> A=array([[1,15,27,8,32],[5,3,4,6,7],[9,104,206,7,302],[0,2,0,3,4]])
>
> I would like to make the same operation with Python. Would you please
> propose me a compact code for achieving that?
>
Hmm, I'm affraid this isn't straightforward. To select arbitrary rows and cols from A you can use
Numeric's take()
In [10]: take(take(A,(0,2),axis=0),(1,2,4),axis=1)
Out[10]:
array([[5, 7, 2],
[4, 6, 2]])
but any operation on the selected submatrix won't alter A. With slicing, e.g. select the upper 2x2 block
In [14]: A[0:2,0:2]
Out[14]:
array([[1, 5],
[5, 3]])
you also can't alter A by performing some operation on the subblock, e.g.
A[0:2,0:2]*100
doesn't change A. Btw, I don't know how to select _arbitrary_ rows and cols with slicing (hints?).
Try to play arround with Numeric's take(), put() (or putmask()) functions. Sry but I don't have any cool elegant idea at
the moment.
Cheers,
Steve
--
Man is the best computer we can put aboard a spacecraft ... and the only one that can be
mass produced with unskilled labor. - Wernher von Braun
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