[SciPy-user] how to make a sinc(x) function - "divide by zero" !
haase at msg.ucsf.edu
Mon Dec 12 12:30:08 CST 2005
Thanks for your reply. (As Perry points out - my code actually works on
But in your code: Don't you get a "division by zero" in Numeric here ?
"where" is evaluation BOTH* results FIRST (over the ENTIRE array) and only
AFTERWARDS "selects" based on the on the first argument
(* actually all "three" arrays)
On Monday 12 December 2005 10:04, Scott Ransom wrote:
> Here is a simple version that I use. It uses the Taylor
> expansion when the argument is near zero. Note that this
> is using Numeric and umath right now. This should be
> trivial to change to new scipy_core (which I am not using yet):
> def sinc(xs):
> Return the sinc function [i.e. sin(pi * xs)/(pi * xs)]
> for the values xs.
> pxs = umath.pi*xs
> return Numeric.where(umath.fabs(pxs)<1e-3,
> 1.0-pxs*pxs/6.0, umath.sin(pxs)/pxs)
> On Monday 12 December 2005 12:39 pm, Arnd Baecker wrote:
> > On Mon, 12 Dec 2005, Sebastian Haase wrote:
> > > Hi,
> > > I was trying to implement a "sinc" [sin(x)/x] in numarray. But the
> > > "where"-semantics makes it choke on the x=0: 0/0 case.
> > > (This should of course work for x being an array - so "if" is no
> > > option) The best I could come up with was:
> > >
> > > def sinc(r):
> > > na.Error.pushMode(all="ignore")
> > > a = na.where(r, na.divide(na.sin(r),r), 1)
> > > na.Error.popMode()
> > > return a
> > >
> > > but I still seem to get a warning...
> > >
> > > >>> F.sinc(0)
> > >
> > > Warning: Encountered invalid numeric result(s) in divide
> > > 1.0
> > >
> > > What is a better way of doing this ?
> > Yuo could try to use `vectorize` (warning: untested code)
> > def sinc(x):
> > if x==0.0: # presumably better to check for small
> > x return 0.0 # here ...
> > else:
> > return sin(x)/x
> > sinc_vectorized=scipy.vectorize(sinc)
> > HTH,
> > Arnd
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