[SciPy-user] mean of arrays...

Gael Varoquaux gael.varoquaux@normalesup....
Thu Sep 6 08:36:23 CDT 2007


On Thu, Sep 06, 2007 at 09:34:17AM -0400, Gary Pajer wrote:
> > listmean = lambda l: concatenate([a[..., newaxis] for a in l],
> >                                                 axis=-1).mean(axis=-1)

> Am I missing something here?
> doesn't numpy.mean() find the mean of all elements regardless of dimension?

That's what the "axis=-1" is for.

Did I make an error ? This should be working, I tested it.

Gaël


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