[SciPy-user] help about a function to solve no linear equations

Jose Lopez lopmart@gmail....
Tue Apr 22 18:37:56 CDT 2008


ok, thank you.

On Tue, Apr 22, 2008 at 1:45 PM, Nils Wagner <nwagner@iam.uni-stuttgart.de>
wrote:

>  On Tue, 22 Apr 2008 13:38:54 -0700
>  "Jose Lopez" <lopmart@gmail.com> wrote:
> > hi
> >
> > somebody know, any function at scipy for solver system
> >no linear equations?
> >
> > thanks
> > atte JL
>
> scipy.optimize.fsolve
>
> fsolve(func, x0, args=(), fprime=None, full_output=0,
> col_deriv=0, xtol=1.49012e-08, maxfev=0, band=None,
> epsfcn=0.0, fact
> or=100, diag=None, warning=True)
>     Find the roots of a function.
>
>     Description:
>
>       Return the roots of the (non-linear) equations
> defined by
>       func(x)=0 given a starting estimate.
>
>     Inputs:
>
>       func -- A Python function or method which takes at
> least one
>               (possibly vector) argument.
>       x0 -- The starting estimate for the roots of
> func(x)=0.
>       args -- Any extra arguments to func are placed in
> this tuple.
>       fprime -- A function or method to compute the
> Jacobian of func with
>               derivatives across the rows. If this is
> None, the
>               Jacobian will be estimated.
>       full_output -- non-zero to return the optional
> outputs.
>       col_deriv -- non-zero to specify that the Jacobian
> function
>                    computes derivatives down the columns
> (faster, because
>                    there is no transpose operation).
>       warning -- True to print a warning message when the
> call is
>                   unsuccessful; False to suppress the
> warning message.
>     Outputs: (x, {infodict, ier, mesg})
>
>       x -- the solution (or the result of the last
> iteration for an
>            unsuccessful call.
>
>
> HTH
>
>         Nils
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