[SciPy-User] typo in odeint docstring

Tony S Yu tsyu80@gmail....
Thu Feb 25 13:26:29 CST 2010


I think the shape of the solutions returned by scipy.integrate.odeint is incorrectly documented: the number of rows matches the number of time steps (in the docstring, N_rows = len(y0))

Example:

>>> from scipy import integrate
>>> import numpy as np
>>> 
>>> x0 = np.ones(5)
>>> dxdt = lambda x, t: x + 1
>>> times = np.linspace(0, 1, 10)
>>> print integrate.odeint(dxdt, x0, times).shape
(10, 5)

Cheers,
-Tony

PS: I know there's some sort of doc editor for scipy. Should I be making the change there instead of emailing the list?

Patch:

Index: scipy/integrate/odepack.py
===================================================================
--- scipy/integrate/odepack.py	(revision 6250)
+++ scipy/integrate/odepack.py	(working copy)
@@ -57,7 +57,7 @@
 
     Returns
     -------
-    y : array, shape (len(y0), len(t))
+    y : array, shape (len(t), len(y0))
         Array containing the value of y for each desired time in t,
         with the initial value y0 in the first row.



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