# [SciPy-User] matrix multiplication

Josh Lawrence josh.k.lawrence@gmail....
Fri Jan 20 14:07:38 CST 2012

You need to specify the first argument of zeros as a tuple:

A = matrix(zeros((3,1)))

That will result in a 3x1 matrix. So

B = A * A.T

will be a 3x3 matrix (3x1 * 1x3).

If you are looking to get a scalar back, you want

A = matrix(zeros((1,3)))
B = A *A.T

When you are not working with matrices, use np.dot(A,A.T).

Cheers,

--Josh

On Jan 20, 2012, at 3:03 PM, Chris Lirakis wrote:

> I have tried the following and they all yield the same result.
>
> A = zeros(3,1)
> B = A * A.T
> B = [[ 0 0 0]
>        [0 0 0]
>        [0  0 0]]
>
> A = matrix(zeros(3,1)
> B = A * A.T
> B = [[ 0 0 0]
>        [0 0 0]
>        [0  0 0]]
>
> I would have thought that the result should have been [[0]]
> if I do the following:
> A = matrix([[0 0 0]]) Then A * A.T yields [[0]]
>
> Can someone tell me why and how I might fix this?
> Chris
>
> --
> Chris Lirakis
>
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